{"id":2674,"date":"2012-07-31T22:03:50","date_gmt":"2012-07-31T22:03:50","guid":{"rendered":"http:\/\/schooltutoring.com\/scholarship\/?p=2674"},"modified":"2014-12-02T08:32:07","modified_gmt":"2014-12-02T08:32:07","slug":"algebra-simultaneous-linear-equations","status":"publish","type":"post","link":"https:\/\/schooltutoring.com\/scholarship\/2012\/07\/31\/algebra-simultaneous-linear-equations\/","title":{"rendered":"Algebra: Simultaneous Linear Equations"},"content":{"rendered":"<p>A linear equation is an equation with the degree 1. It means, the <a href=\"https:\/\/schooltutoring.com\/test-prep-main\/\" target=\"_blank\">highest<\/a> power of the variable in the linear equation is 1. The simultaneous linear equations are set of linear equations with the same variables.<\/p>\n<p><strong><span style=\"text-decoration: underline\">Example:<\/span><\/strong><\/p>\n<p><strong>3x+y=1; x+y=5<\/strong><\/p>\n<h4>Solution of Simultaneous linear equations:<\/h4>\n<p>The set of values of variables which satisfy each and every equation is called the solution of simultaneous linear equations.<\/p>\n<p><strong><span style=\"text-decoration: underline\">Example:<\/span><\/strong><\/p>\n<p><strong>x=-2, y=7<\/strong> is the solution of the simultaneous linear equations <strong>3x+y=1; x+y=5.<\/strong><\/p>\n<h4>Process of finding the solution:<\/h4>\n<p>There are two methods in solving the simultaneous linear equations with <strong>2 <\/strong>variables.<\/p>\n<h4><span style=\"text-decoration: underline\">Method 1:<\/span> Substitution method:<\/h4>\n<p>(i)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Find the value of one variable in terms of the other variable from any one of the 2 given equations.<\/p>\n<p>(ii)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Substitute this value into the other equation (which is not the above selected equation) and here we get a linear equation with one variable.<\/p>\n<p>(iii)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Solve this equation to find the value of the above variable.<\/p>\n<p>(iv)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Substitute this value into the equation from step (i) to find the value of other variable.<\/p>\n<p><strong><span style=\"text-decoration: underline\">Example:<\/span><\/strong><\/p>\n<p>Solve <strong>3x+y=1; x+y=5.<\/strong><\/p>\n<p><em><strong><span style=\"text-decoration: underline\">Solution:<\/span><\/strong><\/em><\/p>\n<p><strong>3x+y=1<\/strong> \u2026 (1)<\/p>\n<p><strong>x+y=5 <\/strong>\u2026 (2)<\/p>\n<p>From equation (2),<\/p>\n<p><strong>y=5-x<\/strong> \u2026 (3)<\/p>\n<p>Substituting this into equation (1),<\/p>\n<p><strong>3x + 5 \u2013 x = 1<\/strong><\/p>\n<p><strong>2x = -4<\/strong><\/p>\n<p><strong>x=-2<\/strong>.<\/p>\n<p>From equation (3),<\/p>\n<p><strong>y = 5-(-2)=5+2=7.<\/strong><\/p>\n<p>So the solution is <strong>x=-2<\/strong> and <strong>y=7.<\/strong><\/p>\n<h4><span style=\"text-decoration: underline\">Method 2:<\/span> \u00a0Adding\/subtracting the equations:<\/h4>\n<p>(i)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Make the coefficient of one of the variables same in both equations.<\/p>\n<p>(ii)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Add or subtract the equations so that the above variable is eliminated and here, we get a new equation with the other variable.<\/p>\n<p>(iii)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 This new equation equation is solved to find this second variable.<\/p>\n<p>(iv)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 This value of the second variable is substituted in any of the given two equations to find the value of first variable.<\/p>\n<p><strong><span style=\"text-decoration: underline\">Example:<\/span><\/strong><\/p>\n<p>Solve <strong>3x+y=1; x+y=5<\/strong>.<\/p>\n<p><em><strong><span style=\"text-decoration: underline\">Solution:<\/span><\/strong><\/em><\/p>\n<p><strong>3x+y=1<\/strong> \u2026 (1)<\/p>\n<p><strong>x+y=5<\/strong> \u2026 (2)<\/p>\n<p>The coefficient of y is already same (as 1) in both the equations.<\/p>\n<p>Subtracting (2) from (1),<\/p>\n<p><strong>2x = -4<\/strong><\/p>\n<p><strong>x= -2.<\/strong><\/p>\n<p>From (2),<\/p>\n<p><strong>-2 + y = 5<\/strong><\/p>\n<p><strong>y = 5+2 = 7.<\/strong><\/p>\n<p>So the solution is <strong>x=-2<\/strong> and <strong>y=7.<\/strong><\/p>\n<p><strong><span style=\"text-decoration: underline\"><br \/>\n<\/span><\/strong><\/p>\n<p><span class=\"tutorOrange\">SchoolTutoring Academy<\/span> is the premier educational services company for K-12 and college students. We offer tutoring programs for students in K-12, AP classes, and college. To learn more about how we help parents and students in Ontario visit: <a href=\"https:\/\/schooltutoring.com\/tutoring-in-ontario-california\/\">Tutoring in Ontario. <\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>A linear equation is an equation with the degree 1. It means, the highest power of the variable in the linear equation is 1. The simultaneous linear equations are set of linear equations with the same variables. Example: 3x+y=1; x+y=5 Solution of Simultaneous linear equations: The set of values of variables which satisfy each and [&hellip;]<\/p>\n","protected":false},"author":19,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"inline_featured_image":false,"footnotes":""},"categories":[2],"tags":[47,588,1646,1682,1752,1759],"class_list":["post-2674","post","type-post","status-publish","format-standard","hentry","category-algebra","tag-adding","tag-equation","tag-simultaneous","tag-solution","tag-substitution","tag-subtracting"],"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/posts\/2674","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/users\/19"}],"replies":[{"embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/comments?post=2674"}],"version-history":[{"count":0,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/posts\/2674\/revisions"}],"wp:attachment":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/media?parent=2674"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/categories?post=2674"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/tags?post=2674"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}