{"id":6591,"date":"2013-12-23T22:26:31","date_gmt":"2013-12-23T22:26:31","guid":{"rendered":"https:\/\/schooltutoring.com\/scholarship\/?p=6591"},"modified":"2014-12-02T08:26:55","modified_gmt":"2014-12-02T08:26:55","slug":"solving-for-a-variable","status":"publish","type":"post","link":"https:\/\/schooltutoring.com\/scholarship\/2013\/12\/23\/solving-for-a-variable\/","title":{"rendered":"Solving for a Variable"},"content":{"rendered":"

Overview:<\/strong><\/p>\n

In order to solve some algebraic equations, it is important to choose a variable within the equation and then solve the equation in terms of that variable.\u00a0One strategy is to get the variable on one side of the equation and the known values on the other side of the equation, then solving the problem.\u00a0Generally, equations can be solved in different ways depending on which variable is isolated, then solved.<\/p>\n

Isolating a Variable<\/strong><\/p>\n

As a general rule, isolating a variable on one side of the equation is a matter of doing the same operation to both sides of the equation.\u00a0The operation will cancel everything out on one side of the equation except for the variable that is chosen.\u00a0The equation that is left is similar, but it is often easier to solve.<\/p>\n

Using Addition or Subtraction<\/strong><\/p>\n

Suppose the equation is a general equation like x + y = z.\u00a0If solving for x, isolate the x on one side of the equation by cancelling out the y, as in x + y -y =z -y, or x = z-y.\u00a0Solving for y is similar, as x -x +y = z – x, so that the x is cancelled out and the y is isolated.\u00a0It can be shown in a less general equation.\u00a0For example, if x +6 = 9, then x = 9-6, or x =3.\u00a0The equation can also be solved in terms of the 6, as 6 = 9-x.<\/p>\n

Using Multiplication or Division<\/strong><\/p>\n

Suppose the equation is the equation of d = rt, where d is distance, r is rate, and t is time. Then, if solving for r, isolate the r on one side of the equation so that rt\/t = d\/t. If solving for t, isolate the t, so that rt\/r = d\/r.\u00a0It can also be shown in a less general equation.\u00a0Suppose 5y = 20.\u00a0Then solving for y will isolate the y so that y = 20\/5 (or 4).\u00a0Similarly, 5 = 20\/y. (Of course, y is not equal to zero, or else the problem is undefined.)<\/p>\n

Using a Combination of Operations<\/strong><\/p>\n

Suppose a problem asks for a combination of operations. It can still be solved by isolating variables, but it will take more than one step. For example, the formula for the perimeter of a rectangle is P = 2l + 2w. Isolating l will take two steps. If 2l = P-2w, then l will equal (P-2w)\/2.\u00a0 Similarly, if 2w = P – 2l, then w will\u00a0 equal (P-2l)\/w.<\/p>\n

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Overview: In order to solve some algebraic equations, it is important to choose a variable within the equation and then solve the equation in terms of that variable.\u00a0One strategy is to get the variable on one side of the equation and the known values on the other side of the equation, then solving the problem.\u00a0Generally, […]<\/p>\n","protected":false},"author":22,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"inline_featured_image":false,"footnotes":""},"categories":[13],"tags":[588,977,1925],"class_list":["post-6591","post","type-post","status-publish","format-standard","hentry","category-pre-algebra","tag-equation","tag-inverses","tag-variable"],"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/posts\/6591","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/users\/22"}],"replies":[{"embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/comments?post=6591"}],"version-history":[{"count":0,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/posts\/6591\/revisions"}],"wp:attachment":[{"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/media?parent=6591"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/categories?post=6591"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/schooltutoring.com\/scholarship\/wp-json\/wp\/v2\/tags?post=6591"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}