The Hardy-Weinberg principle states that both allele and genotype frequencies are in equilibrium in a constant population from generation to generation. This is only true under Hardy-Weinberg conditions, which are:
1) No mutations
– Alleles in the population should not change
2) No natural selection
– A particular individual must not be favoured because of natural selection
3) Infinitely large population
– Small populations increase the chance of random sampling errors
4) Random mating
– There should be no preference in mates
5) No migration in or out of population
– Alleles should not move in/out of the population, there should be no gene flow
These 5 assumptions are important in keeping the Hardy-Weinberg equilibrium.
The Hardy-Weinberg equilibrium is also represented by the equation:
p2 + 2pq + q2 = 1
Where:
p = frequency of the dominant allele (A)
q = frequency of the recessive allele (a)
p + q = 1
Thus, the frequency of AA is denoted by “p2”, the frequency of Aa is denoted by “2pq”, and the frequency of aa is denoted by “q2”.
Sample Question:
If 36% of a population is AA, what percentage of the population is Aa?
Solution:
Frequency of AA is 36% = 0.36 = p2
√0.36 = 0.6
Thus, p = 0.6
p + q = 1
0.6 + q = 1
Thus, q = 0.4
Frequency of Aa = 2pq = 2(0.6)(0.40) = 0.48 = 48%
Therefore, 48% of the population is Aa.
This article was written for you by Samantha, one of the tutors with Test Prep Academy.