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# Equation of a Line – Normal Form

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Normal:

A normal to a line is a line segment drawn from a point perpendicular to the given line.

Let p be the length of the normal drawn from the origin to a line, which subtends an angle ø with the positive direction of x-axis as follows.

Then, we have Cos ø = p/m à m = p/Cos ø

And Sin ø = p/n à n = p/Sin ø

The equation of line in intercept form is,

x/m + y/n =1

x/(p/Cos ø) + y/(p/Sin ø) = 1

x Cos ø/p + y Sin ø/p =1

x Cos ø + y Sin ø = p.

This is called the normal form of equation of the given line making the angle ø with the positive direction of x-axis and whose perpendicular distance from the origin is p.

Converting the general equation of a line into normal form:

The equation of a straight line in general form is,

ax+by+c=0

From the above equations, we have

Cos ø = p/m and Sin ø = p/n

From Trigonometric identity, we have

Cos2 ø + Sin2ø=1

p2/m2 + p2/n2=1

Solving this equation gives us,

P = mn/√(m2+n2), which is the perpendicular distance from the origin to the line x/m + y/n =1 (i.e., nx + my – mn=0)

Thus, we have the distance from origin to the line ax+by+c=0, = |c|/√(a2+b2)

Thus, for converting the given line into normal form, divide the equation ax+by+c=0 by √(a2+b2).
Thus,

[a/ √(a2+b2)] x + [b/√(a2+b2)] + c/√(a2+b2)=0

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